Print first column of passwd
The delimiter used to differentiate different fields in the /etc/passwd files is colon ' : ' . Therefore we need to look only after the semicolon.
To deal with column based files or formatted text the most commonly used command is awk.
Command below will print out the first column of /etc/passwd file:
awk < /etc/passwd -F: '{ print $1 }'
Here
awk is the text processor
< /etc/passwd will serve as input file for awk
-F: is a parameter for awk that specifies the delimiter. In our
case is colon.
{ print $1 } This will print the first line. You can put $2, $3 etc. to
print respective column.
My command produced following output:
root
daemon
bin
sys
adm
lp
uucp
nuucp
smmsp
listen
gdm
webservd
postgres
svctag
nobody
noaccess
nobody4
Labels: Linux, Oracle Linux, RedHat, Scripting, Shell, Solaris, UNIX/Linux
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